The completed program is given below.

Here is the complete program that adds up even and odd integers from zero the limit N specified by the user:

import java.util.Scanner; // User enters a value N // Add up odd integers, // even integers, and all integers 1 to N // class AddUpIntegers { public static void main (String[] args ) { Scanner scan = new Scanner( System.in ); int N, sumAll = 0, sumEven = 0, sumOdd = 0; System.out.print( "Enter limit value: " ); N = scan.nextInt(); int count = 1; while ( count <= N ) { sumAll = sumAll + count ; if ( count % 2 == 0 ) sumEven = sumEven + count ; else sumOdd = sumOdd + count ; count = count + 1 ; } System.out.print ( "Sum of all : " + sumAll ); System.out.print ( "/tSum of even: " + sumEven ); System.out.println( "/tSum of odd : " + sumOdd ); } }

It would be odd if you did not copy and paste this program to Notepad, save it to a file, and run it. An even better idea would be to pretend you had not seen it, and to try to create it from scratch.

Which is larger: the sum of evens or the sum of odds? Does the answer to this question change if N is even or odd?