### Answer:

Using the De Morgan Rule

`!(A && B)`

is equivalent to `!A || !B`

The expression

boolean discount = !( (days < 14) && onSeason );

is equivalent to

boolean discount = !(days < 14) || !onSeason ;

which can be further transformed to

boolean discount = days >= 14 || !onSeason ;

# More De Morgan

De Morgan's rules can be extended to three operands:

`!(A && B && C)`

is equivalent to `!A || !B || !C`

`!(A || B || C)`

is equivalent to `!A && !B && !C`

Expressions with more than three operands behave similarly.

### QUESTION 18:

A driver holding a learner's permit may drive a car only during daylight hours
and only if accompanied by a licensed driver of age 21 or over.

boolean drivingOK = daylight && passenger.age >= 21 && passenger.licensed;

Assume that `passenger`

refers to an object with an integer member `age`

and a boolean member `licensed`

.
Here is an expression that says when driving is not permitted:

boolean noDriving = !(daylight && passenger.age >= 21 && passenger.licensed );

Transform this into a simpler expression.